Eva is three times older than Jibon. Zaheer is half the age of Wahida. Jibon is older than Zaheer . From this information, which of the following can be inferred?
-
ক
Eva is older than Wahida.
-
খ
Jibon is older than Wahida.
-
গ
Eva may be younger than Wahida.
-
ঘ
Jibon and Wahida are at same age .
-
ঙ
None of the above
Let’s translate the statements into relations:
- Eva = 3 × Jibon → E = 3J
- Zaheer = ½ × Wahida → Z = W/2
- Jibon is older than Zaheer → J > Z
So:
J > W/2 → 2J > W → W < 2J
Now compare Eva and Wahida:
- E = 3J
- W < 2J
So clearly:
- 3J > 2J > W
→ E > W always
So Eva is definitely older than Wahida.
Check options:
A. Eva is older than Wahida ✔️ TRUE (always)
B. Jibon is older than Wahida
Not necessarily (J > W/2 does not guarantee J > W)
C. Eva may be younger than Wahida
Impossible (E > W always)
D. Same age
Impossible
Final Answer:
A. Eva is older than Wahida
There’s no way to tell for sure, but Eva may be younger than Wahida.
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